python 如何获取页面所有a标签下href的值

这篇文章主要介绍了python 获取页面所有a标签下href的值操作，具有很好的参考价值，希望对大家有所帮助。一起跟随小编过来看看吧

看代码吧~

 # -*- coding:utf-8 -*- #python 2.7 #http://tieba.baidu.com/p/2460150866 #标签操作 from bs4 import BeautifulSoup import urllib.request import re #如果是网址，可以用这个办法来读取网页 #html_doc = "http://tieba.baidu.com/p/2460150866" #req = urllib.request.Request(html_doc) #webpage = urllib.request.urlopen(req) #html = webpage.read() html=""" The Dormouse's story The Dormouse's story
Once upon a time there were three little sisters; and their names were , Lacie and Tillie; Lacie and they lived at the bottom of a well.
...
 """ soup = BeautifulSoup(html, 'html.parser')   #文档对象 #查找a标签,只会查找出一个a标签 #print(soup.a)# for k in soup.find_all('a'): print(k) print(k['class'])#查a标签的class属性 print(k['id'])#查a标签的id值 print(k['href'])#查a标签的href值 print(k.string)#查a标签的string

中含有其他标签，比如..，此时要提取中的数据，需要用k.get_text()

 soup = BeautifulSoup(html, 'html.parser')   #文档对象 #查找a标签,只会查找出一个a标签 for k in soup.find_all('a'): print(k) print(k['class'])#查a标签的class属性 print(k['id'])#查a标签的id值 print(k['href'])#查a标签的href值 print(k.string)#查a标签的string

中含有其他标签，比如..，此时要提取中的数据，需要用k.get_text()

通常我们使用下面这种模式也是能够处理的，下面的方法使用了get()。

 html = urlopen(url) soup = BeautifulSoup(html, 'html.parser') t1 = soup.find_all('a') print t1 href_list = [] for t2 in t1: t3 = t2.get('href') href_list.append(t3)

补充：python爬虫获取任意页面的标签和属性（包括获取a标签的href属性）

看代码吧~

 # coding=utf-8 from bs4 import BeautifulSoup import requests # 定义一个获取url页面下label标签的attr属性的函数 def getHtml(url, label, attr): response = requests.get(url) response.encoding = 'utf-8' html = response.text soup = BeautifulSoup(html, 'html.parser'); for target in soup.find_all(label): try: value = target.get(attr) except: value = '' if value: print(value) url = 'https://baidu.com/' label = 'a' attr = 'href' getHtml(url, label, attr)