这篇文章主要介绍了R语言在散点图中添加lm线性回归公式的问题,本文通过实例代码给大家介绍的非常详细，对大家的学习或工作具有一定的参考借鉴价值，需要的朋友可以参考下
1. 简单的线性回归
函数自带的例子（R 中键入?lm），lm(y ~ x)回归y=kx + b， lm( y ~ x -1 )省略b，不对截距进行估计：
require(graphics) ## Annette Dobson (1990) "An Introduction to Generalized Linear Models". ## Page 9: Plant Weight Data. ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14) trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69) group <- gl(2, 10, 20, labels = c("Ctl","Trt")) weight <- c(ctl, trt) lm.D9 <- lm(weight ~ group) lm.D90 <- lm(weight ~ group - 1) # omitting intercept anova(lm.D9) summary(lm.D90) opar <- par(mfrow = c(2,2), oma = c(0, 0, 1.1, 0)) plot(lm.D9, las = 1) # Residuals, Fitted, ... par(opar) 使用R中自带的mtcars数据，可以得到截距和斜率，也可以得到解释率R-square：
require(ggplot2) library(dplyr) #加载dplyr包 library(ggpmisc) #加载ggpmisc包 library(ggpubr) require(gridExtra) model=lm(mtcars$wt ~ mtcars$mpg) model ## 输出： Call: lm(formula = mtcars$wt ~ mtcars$mpg) Coefficients: (Intercept) mtcars$mpg 6.047 -0.141 ``` ```handlebars summary(model) ## 输出： Call: lm(formula = mtcars$wt ~ mtcars$mpg) Residuals: Min 1Q Median 3Q Max -0.652 -0.349 -0.138 0.319 1.368 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 6.0473 0.3087 19.59 <2e-16 *** mtcars$mpg -0.1409 0.0147 -9.56 1.3e-10 --- signif. codes: 0 ‘***' 0.001 ‘**' 0.01 ‘*' 0.05 ‘.' 0.1 ‘ ' 1 residual standard error: 0.494 on 30 degrees of freedom multiple r-squared: 0.753, adjusted 0.745 f-statistic: 91.4 and df, p-value: 1.29e-10 < pre>
提取回归R-square值：
通过summary提取： ## 上面的例子 ## mtcars例子 model=lm(mtcars$wt ~ mtcars$mpg) res=summary(model) str(res) ## 提取各个值： res$r.squared res$coefficients res$adj.r.squared ## df 矫正后的结果 res$coefficients[1,1] res$coefficients[2,1]
使用默认的plot绘制回归散点：
plot(mtcars$mpg, mtcars$wt, pch=20,cex=2) abline(model,col="red",lwd=2)
计算Confidence interval（95%）：
test=mtcars[c("mpg","wt")] head(test) colnames(test)=c("x","y") model = lm(y ~ x, test) test$predicted = predict( object = model, newdata = test) test$CI = predict( object = model, newdata = test, se.fit = TRUE )$se.fit * qt(1 - (1-0.95)/2, nrow(test)) test$predicted = predict( object = model, newdata = test) test$CI_u=test$predicted+test$CI test$CI_l=test$predicted-test$CI plot(mtcars$mpg, mtcars$wt, pch=20,cex=1) ## have replicated x values abline(model,col="red",lwd=2) lines(x=test$x,y=test$CI_u,col="blue") lines(x=test$x,y=test$CI_l,col="blue") 
上面的图蓝线有点奇怪，简单绘制最初的plot：
plot(mtcars$mpg, mtcars$wt, pch=20,cex=1,type="b") ## have replicated x values
实际上面的计算方法没问题，但是数据不合适，因为数据x含有重复值，所以要考虑这个。
2. 使用ggplot2展示
ggplot2例子：
p <- ggplot(df, aes(x=yreal, y=ypred)) + geom_point(color = "grey20",size = 1, alpha = 0.8) #回归线 #添加回归曲线 p2 <- p + geom_smooth(formula = y ~ x, color = "red", fill = "blue", method = "lm",se = T, level=0.95) + theme_bw() + stat_poly_eq( aes(label = paste(..eq.label.., ..adj.rr.label.., sep = '~~~')), formula = y ~ x, parse = TRUE,color="blue", size = 5, #公式字体大小 label.x = 0.05, #位置 ，0-1之间的比例 label.y = 0.95) + labs(title="test",x="Real Value (Huang Huaihai 1777)" , y="Predicted Value (Correlation: 0.5029)") p2
ggplot版本的手动计算：
require(ggplot2) library(dplyr) #加载dplyr包 library(ggpmisc) #加载ggpmisc包 library(ggpubr) require(gridExtra) ggplot(data=df, aes(x=yreal, y=ypred)) + geom_smooth(formula = y ~ x, color = "blue", fill = "grey10", method = "lm") + geom_point() + stat_regline_equation(label.x=0.1, label.y=-1.5) + stat_cor(aes(label=..rr.label..), label.x=0.1, label.y=-2) test=df head(test) colnames(test)=c("x","y") model = lm(y ~ x, test) test$predicted = predict( object = model, newdata = test) test$CI = predict( object = model, newdata = test, se.fit = TRUE )$se.fit * qt(1 - (1-0.95)/2, nrow(test)) ggplot(test) + aes(x = x, y = y) + geom_point(size = 1,colour="grey40") + geom_smooth(formula =y ~ x,method = "lm", fullrange = TRUE, color = "black") + geom_line(aes(y = predicted + CI), color = "blue") + # upper geom_line(aes(y = predicted - CI), color = "red") + # lower theme_classic() 
参考：
https://stackoverflow.com/questions/23519224/extract-r-square-value-with-r-in-linear-models （提取R2）
https://blog.csdn.net/LeaningR/article/details/118971000 （提取R2等）
https://stackoverflow.com/questions/45742987/how-is-level-used-to-generate-the-confidence-interval-in-geom-smooth （添加lm线）
https://zhuanlan.zhihu.com/p/131604431 （知乎）
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