Oracle排名函数(Rank)实例详解

 select * from ( select sc.s_id,sc.s_name,sub_name,sc.score, dense_rank() over (partition by sub_name order by score desc) 名次 from t_score sc ) x where x.名次<=2

 create table t_score ( autoid number primary key, s_id  number(3), s_name char(8) not null, sub_name varchar2(20), score number(10,2) ); insert into t_score (autoid, s_id, s_name, sub_name, score) values (8, 1, '张三 ', '语文', 80); insert into t_score (autoid, s_id, s_name, sub_name, score) values (9, 2, '李四 ', '数学', 80); insert into t_score (autoid, s_id, s_name, sub_name, score) values (10, 1, '张三 ', '数学', 0); insert into t_score (autoid, s_id, s_name, sub_name, score) values (11, 2, '李四 ', '语文', 50); insert into t_score (autoid, s_id, s_name, sub_name, score) values (12, 3, '张三丰 ', '语文', 10); insert into t_score (autoid, s_id, s_name, sub_name, score) values (13, 3, '张三丰 ', '数学', null); insert into t_score (autoid, s_id, s_name, sub_name, score) values (14, 3, '张三丰 ', '体育', 120); insert into t_score (autoid, s_id, s_name, sub_name, score) values (15, 4, '杨过 ', 'java', 90); insert into t_score (autoid, s_id, s_name, sub_name, score) values (16, 5, 'mike ', 'c++', 80); insert into t_score (autoid, s_id, s_name, sub_name, score) values (3, 3, '张三丰 ', 'oracle', 0); insert into t_score (autoid, s_id, s_name, sub_name, score) values (4, 4, '杨过 ', 'oracle', 77); insert into t_score (autoid, s_id, s_name, sub_name, score) values (17, 2, '李四 ', 'oracle', 77); commit;