Python制作简单的剪刀石头布游戏

这篇文章主要介绍了Python制作剪刀石头布游戏的方法，帮助大家更好的理解和使用python，感兴趣的朋友可以了解下

关于程序相关的

您可以反复玩游戏，直到选择停止为止。
该程序跟踪获胜情况。
大小写无关紧要（即ROCK与Rock相同）。
如果您输入的内容无效，程序会一直提示您，直到您输入有效的内容。

对项目进行编码的步骤：

创建一个简单的单轮游戏版本，我们不执行正确的输入。
如果输入了无效的内容，则添加while循环可重新提示用户输入选择。
使用while循环让用户反复播放，并使用变量来跟踪得分。

程序代码

 import random input("Welcome to Rock, Paper, Scissors! Press Enter to start.") print() user_wins = 0 computer_wins = 0 choices = ["rock", "paper", "scissors"] while True: random_index = random.randint(0,2) cpu_choice = choices[random_index] user_choice = input("Rock, Paper, or Scissors? ").lower() while user_choice not in choices: user_choice = input("That is not a valid choice. Please try again: ").lower() print() print("Your choice:", user_choice) print("Computer's choice:", cpu_choice) print() if user_choice == 'rock': if cpu_choice == 'rock': print("It's a tie!") elif cpu_choice == 'scissors': print("You win!") user_wins+=1 elif cpu_choice == 'paper': print("You lose!") computer_wins+=1 elif user_choice == 'paper': if cpu_choice == 'paper': print("It's a tie!") elif cpu_choice == 'rock': print("You win!") user_wins+=1 elif cpu_choice == 'scissors': print("You lose!") computer_wins+=1 elif user_choice == 'scissors': if cpu_choice == 'scissors': print("It's a tie!") elif cpu_choice == 'paper': print("You win!") user_wins+=1 elif cpu_choice == 'rock': print("You lose!") computer_wins+=1 print() print("You have "+str(user_wins)+" wins") print("The computer has "+str(computer_wins)+" wins") print() repeat = input("Play again? (Y/N) ").lower() while repeat not in ['y', 'n']: repeat = input("That is not a valid choice. Please try again: ").lower() if repeat == 'n': break print("\n----------------------------\n")