idea搭建ssh框架的超详细教程

这篇文章主要介绍了idea搭建ssh框架的超详细教程，本文通过图文实例代码相结合给大家介绍的非常详细，对大家的学习或工作具有一定的参考借鉴价值,需要的朋友可以参考下

一。创建项目

先附上测试的数据库

DROP TABLE IF EXISTS `user`; CREATE TABLE `user` ( `id` int(5) NOT NULL AUTO_INCREMENT, `name` varchar(10) COLLATE utf8_bin DEFAULT NULL, `password` varchar(10) COLLATE utf8_bin DEFAULT NULL, `remark` varchar(50) COLLATE utf8_bin DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8 COLLATE=utf8_bin; -- ---------------------------- -- Records of user -- ---------------------------- INSERT INTO `user` VALUES ('1', 'zhangsan', '123456', null); INSERT INTO `user` VALUES ('2', 'lisi', '123', null); INSERT INTO `user` VALUES ('3', 'wangan', '456', null); INSERT INTO `user` VALUES ('4', 'xinxi', '000', null);

1.new->project出现如下

点击next后出现如下填写GroupId和ArtifactId在点击next直至finish

2.构建目录结构

在main下新建java和resources目录如下并将java目录标记为Sources Root，resources标记为Resources Root

在java下新建如下包package

二。Struts2

1.首先引入struts2依赖

注：如果引入所有（spring和hibernate）依赖则在struts.xml中的对应action的类class就会找不到

 org.apache.strutsstruts2-core2.5.1 org.apache.strutsstruts2-json-plugin2.5.1compile

2.WEB-INF下web.xml文件配置

  Archetype Created Web Application struts2org.apache.struts2.dispatcher.filter.StrutsPrepareAndExecuteFilter/*

3.在resources下添加struts.xml文件

    test.jsp

4.在action包下创建TestAction类，为了测试在webapp下新建了test.jsp页面

package com.well.liu.action; import com.opensymphony.xwork2.ActionSupport; public class TestAction extends ActionSupport { public String test(){ System.out.println("测试struts2"); return "test"; } }

5.部署

点击如下图

点击+号找到Local

接下来修改名字，选择Deployment点击+号，选择ssh:war exploded,另外Application context填写的如果是ssh，那么访问的时候就是localhost:8080/ssh,部署结束。

6.启动测试

启动后默认访问的是index.jsp页面，可以访问http://localhost:8080/ssh/test

如果页面乱码在头部加上<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>

三。Spring

1.首先引入spring相关依赖

 org.springframeworkspring-context3.0.6.RELEASE org.springframeworkspring-context-support3.0.6.RELEASE org.springframeworkspring-webmvc3.0.6.RELEASE org.springframeworkspring-jdbc3.0.6.RELEASE org.springframeworkspring-orm3.0.6.RELEASE org.springframeworkspring-tx3.0.6.RELEASE org.aspectjaspectjweaver1.8.4 commons-loggingcommons-logging1.2 org.apache.strutsstruts2-spring-plugin2.5.1

2.在web.xml中添加listener,并在resources下新建spring,xml文件

 org.springframework.web.context.ContextLoaderListener contextConfigLocationclasspath:spring.xml

spring.xml文件

如果你的spring.xml文件uri地址出错，解决点击菜单栏“File”→“Settings”→“Languages&Frameworks”

将之前的struts.xml中的class改为"test",也就是说与spring.xml中bean的id相对应，然后运行即可

四。Hibernate

1.引入hibernate依赖

  org.hibernatehibernate-core3.6.5.Final mysqlmysql-connector-java5.1.34 commons-dbcpcommons-dbcp1.4

2.View--》Tool windows---->Database

找到所需连接的数据库

依次填写如下即可

右键点击项目添加support支持

找到Hibernate并且打勾添加 import database schema打勾含义:导入数据库模式

填写如下信息（数据源、实体生成包model位置、勾选需要生成的实体、勾选右下角最下面的两个按钮）即可生成实体和映射文件

3.编写代码

spring.xml文件

      com/well/liu/model/UserEntity.hbm.xml  org.hibernate.dialect.MySQL5Dialectfalse

在包dao下新建UserDao

package com.well.liu.dao; import com.well.liu.model.UserEntity; import org.springframework.orm.hibernate3.support.HibernateDaoSupport; public class UserDao extends HibernateDaoSupport { public UserEntity getUser(int id){ return this.getHibernateTemplate().get(UserEntity.class,id); } }

在包service下新建UserService

package com.well.liu.service; import com.well.liu.model.UserEntity; public interface UserService { public UserEntity getUser(int id); }

在包impl下新建UserServiceImpl

package com.well.liu.service.impl; import com.well.liu.dao.UserDao; import com.well.liu.model.UserEntity; import com.well.liu.service.UserService; public class UserServiceImpl implements UserService { private UserDao userDao; public UserDao getUserDao() { return userDao; } public void setUserDao(UserDao userDao) { this.userDao = userDao; @Override public UserEntity getUser(int id) { UserEntity userEntity = userDao.getUser(id); return userEntity; }

TestAction类

package com.well.liu.action; import com.opensymphony.xwork2.ActionSupport; import com.well.liu.model.UserEntity; import com.well.liu.service.UserService; public class TestAction extends ActionSupport { private UserService userService; public UserService getUserService() { return userService; } public void setUserService(UserService userService) { this.userService = userService; public String test(){ UserEntity userEntity = userService.getUser(1); System.out.println(userEntity); return "test"; }

启动后会报如下错误