JAVA删除字符串固定下标字串的实现

本文主要介绍了JAVA删除字符串固定下标字串的实现，文中通过示例代码介绍的非常详细，对大家的学习或者工作具有一定的参考学习价值，需要的朋友们下面随着小编来一起学习学习吧

需要修改的报文

当你拿到的报文是这样的

{ "input": { "sdfsn": "23u4209350-2", "fsfs": "128412094", "sgsgsg": "15821059", "inssgsuplc_admdfdfdvs": "125125332", "dgh": "125215312", "dfgdfg": "215215", "sdhdsh": "", "sdfsn": "", "shdfshdshdsh": "shsdh", "sdhdsh": "shsh.0", "shsdhsd": "1", "shsdh": "1607", "input": { "data": { "dhfsdhsd": "235325", "shsdhsdh": "03", "dgd": "BE0445360", "dfhfdh": "11", "dshshsd": 76.56, "ghjrfgj": "01", "grjf": "234623626", "hjfd": "236436", "djfdfgjdfj": "45634", "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}", "dfjgdfj": "", "dfjdfjgdfj": "56745745", "dfgjdfgjh": 45756758, "jdfgjhfdgj": 0, } } }, "output": { "output": { "r757": { "dhfsdhsd": "235325", "shsdhsdh": "03", "dgd": "BE0445360", "dfhfdh": "11", "dshshsd": 76.56, "ghjrfgj": "01", "grjf": "234623626", "hjfd": "236436", "djfdfgjdfj": "45634", "exp_content": "", "dfjgdfj": "", "dfjdfjgdfj": "56745745", "dfgjdfgjh": 45756758, "jdfgjhfdgj": 0, }, "sdfgsdfg": [ { "sgasgag": "4673476", "agasgdas": 5675467, "asgasgasg": "", "asdgasgas": 4567456754, "dhsdsxchsdh": 54675467, "sdfhsdhsdh": "5674756457" } ] }, "erherth": 0, } }

这一看就知道上边的报文在postman里边肯定会报错，因为exp_Content，因此他又没有用到，所以你想把他删掉。其实也没那么难删

也就是用到了流转字符串。字符串固定字符查找，然后进行字符串转字符流，删掉字符流中固定字符，之后再转回来。因为字符串已经是final了所以很多用法都是使用字符串转字符流实现的

实现代码如下

    private JSONObject resolveApplicationJson(HttpServletRequest request) { InputStream is = null; String json = null; try { is = request.getInputStream(); json = IOUtils.toString(is, "UTF-8"); json=json.replaceAll("\\r|\n|\t",""); int index=  json.indexOf("exp_Content"); int indexfirst=json.indexOf("{", index); int indexlast=json.indexOf("}",index); if (index!=-1 && indexlast !=-1 &&indexfirst !=-1) { StringBuffer stringBuffer = new StringBuffer(json); stringBuffer.delete(indexfirst,indexlast+1); json=stringBuffer.toString(); } } catch (IOException e) { throw new RuntimeException("CANNOT get reader from request!", e); } finally { if (is != null) { try { is.close(); } catch (IOException e) { e.printStackTrace(); } } } try { return new JSONObject(json); } catch (JSONException e) { throw new RuntimeException("CANOT CONVET JSON:[" + json + "] to JSONObject!", e); } }

多存在多个不符合规定的数据然后你要删掉怎么操作呢？

这也很简单，如果你看了这一篇文章，你要更好的解决方式，期待一起探讨，学习进步(＾－＾)V

当你拿到的报文是这样的。

{ "input": { "sdfsn": "23u4209350-2", "fsfs": "128412094", "sgsgsg": "15821059", "inssgsuplc_admdfdfdvs": "125125332", "dgh": "125215312", "dfgdfg": "215215", "sdhdsh": "", "sdfsn": "", "shdfshdshdsh": "shsdh", "sdhdsh": "shsh.0", "shsdhsd": "1", "shsdh": "1607", "input": { "data": { "dhfsdhsd": "235325", "shsdhsdh": "03", "dgd": "BE0445360", "dfhfdh": "11", "dshshsd": 76.56, "ghjrfgj": "01", "grjf": "234623626", "hjfd": "236436", "djfdfgjdfj": "45634", "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}", "dfjgdfj": "", "dfjdfjgdfj": "56745745", "dfgjdfgjh": 45756758, "jdfgjhfdgj": 0, } } }, "output": { "output": { "r757": { "dhfsdhsd": "235325", "shsdhsdh": "03", "dgd": "BE0445360", "exp_Content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}", "dfhfdh": "11", "dshshsd": 76.56, "ghjrfgj": "01", "grjf": "234623626", "hjfd": "236436", "djfdfgjdfj": "45634", "exp_content": "{"gdsg":"01","gjfj":"658568","fjfj":"5675467","ghfjfgkj":"68568","vmgfvj":"658568","gfhjgfyk":"0","fghkfghkg":"5474567"}", "dfjgdfj": "", "dfjdfjgdfj": "56745745", "dfgjdfgjh": 45756758, "jdfgjhfdgj": 0, }, "sdfgsdfg": [ { "sgasgag": "4673476", "agasgdas": 5675467, "asgasgasg": "", "asdgasgas": 4567456754, "dhsdsxchsdh": 54675467, "sdfhsdhsdh": "5674756457" } ] }, "erherth": 0, } }

解决方式如下：根据需要写出正则表达式，再使用正则看看有几个这样的不需要的符号，然后循环遍历几次，之后找到这部分，最后删除掉。

实现代码如下

# 全局变量 private static String REGEX = "exp_[c,C]ontent"; # 方式方法 Pattern p = Pattern.compile(REGEX); // 获取 matcher 对象 Matcher m = p.matcher(JSON); List list = new ArrayList(); while(m.find()){ list.add(m.start()); } int index=0; int indexfirst=0; int indexlast=0; for (int j = 0; j

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