ajax 防止用户反复提交的2种解决方案
ajax 防止重复提交可以通过在服务器端加载方法或直接写在页面脚本里，具体实现如下，遇到重复提交情况的朋友可以参考下，希望对大家有所帮助
可在服务器端加载方法：
private void OnLoading()
{
System.Text.StringBuilder sb = new System.Text.StringBuilder();
sb.Append(" function pageLoad(){var manager = Sys.WebForms.PageRequestManager.getInstance(); ");
sb.Append(" manager.add_beginRequest(OnBeginRequest); manager.add_endRequest(OnEndRequest)} var lcPostbackElementID;");
sb.Append(" function OnBeginRequest(sender, args){ lcPostbackElementID = args.get_postBackElement().id.toLowerCase(); if (lcPostbackElementID === \"btnadwords\"){$get(\"btnAdWords\").disabled = true; $get(\"btnAdWords\").value='正在提交...';}} ");
sb.Append(" function OnEndRequest(sender, args){if (lcPostbackElementID === \"btnadwords\"){ $get(\"btnAdWords\").disabled = false; $get(\"btnAdWords\").value='确定';}} ");
ScriptManager.RegisterStartupScript(Page, Page.GetType(), "btnAdWords", sb.ToString(), true);
}
也可直接写在页面脚本里：
复制代码 代码如下:
private void OnLoading()
{
System.Text.StringBuilder sb = new System.Text.StringBuilder();
sb.Append(" function pageLoad(){var manager = Sys.WebForms.PageRequestManager.getInstance(); ");
sb.Append(" manager.add_beginRequest(OnBeginRequest); manager.add_endRequest(OnEndRequest)} var lcPostbackElementID;");
sb.Append(" function OnBeginRequest(sender, args){ lcPostbackElementID = args.get_postBackElement().id.toLowerCase(); if (lcPostbackElementID === \"btnadwords\"){$get(\"btnAdWords\").disabled = true; $get(\"btnAdWords\").value='正在提交...';}} ");
sb.Append(" function OnEndRequest(sender, args){if (lcPostbackElementID === \"btnadwords\"){ $get(\"btnAdWords\").disabled = false; $get(\"btnAdWords\").value='确定';}} ");
ScriptManager.RegisterStartupScript(Page, Page.GetType(), "btnAdWords", sb.ToString(), true);
}
也可直接写在页面脚本里：
复制代码 代码如下: